Python Set difference_update() Method
The set.difference_update() method updates the set on which the method is called with the elements that are common in another set passed as an argument.
Syntax:
set.difference_update(another_set)Parameters:
another_set: (Required.) The set with which the difference is to be found.
Return type:
No return value.
The following example demonstrates the set.difference_update() method.
Example: difference_update()
empids = {1,2,3,4,5}
mgrids = {1,2,3}
empids.difference_update(mgrids)
print("empids: ", empids)
print("mgrids: ", mgrids)
Output
empids: {4, 5}
mgrids: {1, 2, 3}
In the above example, empids.difference_update(mgrids) updates the empids set by removing command elements present in mgrids.
The following example demonstrates difference_update() method with the string elements.
Example: difference_update()
cities = {'Mumbai','Chicago','Honk Kong','New York'}
otherCities = {'Mumbai','Chicago'}
cities.difference_update(otherCities)
print("Updated cities: ", cities)
print("otherCities: ", otherCities)
Output
Updated cities: {'Honk Kong', 'New York'}
otherCities: {'Mumbai', 'Chicago'}